Problem

-------

You receive a credit C at a local store and would like to buy two items. You first walk through the store and create a list L of all available items. From this list you would like to buy two items that add up to the entire value of the credit. The solution you provide will consist of the two integers indicating the positions of the items in your list (smaller number first).

Input

-----

The first line of input gives the number of cases, N. N test cases follow. For each test case there will be:

One line containing the value C, the amount of credit you have at the store.

One line containing the value I, the number of items in the store.

One line containing a space separated list of I integers. Each integer P indicates the price of an item in the store.

Each test case will have exactly one solution.

Output

------

For each test case, output one line containing "Case #x: " followed by the indices of the two items whose price adds up to the store credit. The lower index should be output first.

Limits

------

5 ≤ C ≤ 1000

1 ≤ P ≤ 1000

Small dataset

-------------

N = 10

3 ≤ I ≤ 100

Large dataset

-------------

N = 50

3 ≤ I ≤ 2000

Sample Input

------------

3

100

3

5 75 25

200

7

150 24 79 50 88 345 3

8

8

2 1 9 4 4 56 90 3

Output

------

Case #1: 2 3

Case #2: 1 4

Case #3: 4 5

This is one of the easiest problems, I've ever seen in a programming competition. Below is the solution in Java:

What about reading the input? Dont you have to do so?

ReplyDeleteHello Chapucillas,

ReplyDeleteThe 'Reading of Input' part is left to you, to code. All the solutions on this site, concentrate on the actual logic of the problem solution.

i was thinking the second loop could start from i+1, i.e. j=i+1 so that we don't compare items we have already compared their prices

ReplyDelete